# Lesson 8 Flashcards

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<summary><strong>1. What are the two error modes in detection?</strong></summary>
<div class="card-answer"><p>A <strong>miss</strong> (target present, threshold not crossed; probability <span class="math notranslate nohighlight">\(1-P_d\)</span>) and a <strong>false alarm</strong> (noise alone crosses the threshold; probability <span class="math notranslate nohighlight">\(P_{fa}\)</span>).</p></div>
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<summary><strong>2. Give the noise-floor formula.</strong></summary>
<div class="card-answer"><p><span class="math notranslate nohighlight">\(N_{\text{dBm}} = -174 + 10\log_{10}(B_{\text{Hz}}) + \text{NF}_{\text{dB}}\)</span>: cold-receiver density at 290 K, plus bandwidth, plus receiver noise figure.</p></div>
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<summary><strong>3. Compute the noise floor for <span class="math notranslate nohighlight">\(B=10\)</span> MHz, NF <span class="math notranslate nohighlight">\(=3\)</span> dB.</strong></summary>
<div class="card-answer"><p><span class="math notranslate nohighlight">\(N = -174 + 70 + 3 = -101\)</span> dBm. Narrowing to 1 MHz drops it 10 dB to <span class="math notranslate nohighlight">\(-111\)</span> dBm.</p></div>
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<summary><strong>4. What happens to <span class="math notranslate nohighlight">\(P_d\)</span> and <span class="math notranslate nohighlight">\(P_{fa}\)</span> as you raise the threshold?</strong></summary>
<div class="card-answer"><p>Both go down: fewer noise spikes survive (lower <span class="math notranslate nohighlight">\(P_{fa}\)</span>), but some real returns are rejected too (lower <span class="math notranslate nohighlight">\(P_d\)</span>). You can't lower one without the other unless SNR rises.</p></div>
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<summary><strong>5. What SNR does a common operating point require?</strong></summary>
<div class="card-answer"><p><span class="math notranslate nohighlight">\(P_d=0.9\)</span> at <span class="math notranslate nohighlight">\(P_{fa}=10^{-6}\)</span> on a steady target needs about <strong>13 dB</strong>. A fluctuating (Swerling I) target needs much more, around 21 dB.</p></div>
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<summary><strong>6. What does a ROC curve plot, and what does higher SNR do to it?</strong></summary>
<div class="card-answer"><p><span class="math notranslate nohighlight">\(P_d\)</span> versus <span class="math notranslate nohighlight">\(P_{fa}\)</span> (log axis) as the threshold sweeps. Higher SNR pushes the curve toward the top-left corner — the ideal detector.</p></div>
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<summary><strong>7. Why is the ROC curve useful?</strong></summary>
<div class="card-answer"><p>It converts a commander's preference (a tolerable <span class="math notranslate nohighlight">\(P_{fa}\)</span> and required <span class="math notranslate nohighlight">\(P_d\)</span>) into a single engineering spec: the required SNR at the detector input.</p></div>
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<summary><strong>8. Coherent vs non-coherent integration gain for <span class="math notranslate nohighlight">\(N\)</span> pulses?</strong></summary>
<div class="card-answer"><p>Coherent: gain <span class="math notranslate nohighlight">\(=N\)</span>, i.e. <span class="math notranslate nohighlight">\(+10\log_{10}N\)</span> dB (100 pulses → 20 dB). Non-coherent: gain <span class="math notranslate nohighlight">\(\approx\sqrt{N}\)</span>, i.e. <span class="math notranslate nohighlight">\(\approx +5\log_{10}N\)</span> dB (100 pulses → ~10 dB).</p></div>
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<summary><strong>9. What does coherent integration require?</strong></summary>
<div class="card-answer"><p>Phase coherence across the whole dwell — summing complex returns with phase preserved. Modern AESAs are built to maintain it.</p></div>
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<summary><strong>10. Write <span class="math notranslate nohighlight">\(S_{\min}\)</span> in terms of the detection contract.</strong></summary>
<div class="card-answer"><p><span class="math notranslate nohighlight">\(S_{\min} = kTB\cdot\text{NF}\cdot\text{SNR}_{\text{req}}/G_{\text{int}}\)</span>. It is a <span class="math notranslate nohighlight">\(P_d/P_{fa}\)</span> contract, not a constant.</p></div>
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<summary><strong>11. How does 20 dB of integration gain change <span class="math notranslate nohighlight">\(R_{\max}\)</span>?</strong></summary>
<div class="card-answer"><p><span class="math notranslate nohighlight">\(S_{\min}\)</span> drops 20 dB; since <span class="math notranslate nohighlight">\(R_{\max}\propto S_{\min}^{-1/4}\)</span>, range gains <span class="math notranslate nohighlight">\(20/4=5\)</span> dB — a factor of <span class="math notranslate nohighlight">\(\approx 3.2\times\)</span> in km. A longer dwell becomes a longer range.</p></div>
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<summary><strong>12. A radar tightens <span class="math notranslate nohighlight">\(P_{fa}\)</span> from <span class="math notranslate nohighlight">\(10^{-6}\)</span> to <span class="math notranslate nohighlight">\(10^{-9}\)</span>. Effect on <span class="math notranslate nohighlight">\(R_{\max}\)</span>?</strong></summary>
<div class="card-answer"><p>It shortens. A tighter false-alarm contract needs a few more dB of SNR to hold the same <span class="math notranslate nohighlight">\(P_d\)</span>, raising <span class="math notranslate nohighlight">\(S_{\min}\)</span> and shrinking range.</p></div>
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