# Lesson 13 Flashcards

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<summary><strong>1. Why is AoA the only "spatial" field in the PDW?</strong></summary>
<div class="card-answer"><p>Every other field — frequency, pulse width, TOA, power — is a timing measurement on a single antenna and says <em>what</em> the emitter is. AoA depends on geometry and says <em>where</em> it is. It is also the only field that needs more than one antenna (or one receiver) to resolve.</p></div>
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<summary><strong>2. What does AoA do for the receiver that the other fields cannot?</strong></summary>
<div class="card-answer"><p>It <strong>deinterleaves</strong> — splitting emitters that share a band when their pulses overlap, since pulses from different bearings arrive at different angles — and it <strong>cues</strong> the aircrew and steers countermeasures at the right threat.</p></div>
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<summary><strong>3. Why is AoA the hardest PDW field to measure well?</strong></summary>
<div class="card-answer"><p>It is geometry, not timing, measured from a maneuvering aircraft with no scanning dish. And a single bearing is only a <em>line</em>, not a fix — a position needs two bearings crossed (L14).</p></div>
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<summary><strong>4. What are the two physical handles a passive receiver has on bearing?</strong></summary>
<div class="card-answer"><p><strong>Amplitude</strong> — how loud the signal is in beams pointing different ways — and <strong>phase</strong> — how the wavefront arrives at antennas spaced apart. These give amplitude comparison and phase interferometry.</p></div>
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<summary><strong>5. How does amplitude comparison find a bearing?</strong></summary>
<div class="card-answer"><p>Several broad antennas are squinted in different directions so their patterns overlap; the classic RWR uses <strong>four, one per quadrant</strong>. A signal off boresight is louder in the nearer beam, and the power ratio between adjacent beams gives bearing within the overlap.</p></div>
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<summary><strong>6. What are the strengths and the accuracy limit of amplitude comparison?</strong></summary>
<div class="card-answer"><p>It is <strong>single-pulse</strong>, wideband, cheap, and degrades gracefully. Its accuracy is limited by how well each antenna pattern is known (calibration), landing within roughly <span class="math notranslate nohighlight">\(10\text{–}30^\circ\)</span> — enough to label a quadrant, not to target.</p></div>
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<summary><strong>7. Why does an off-boresight wave produce a phase difference across an interferometer?</strong></summary>
<div class="card-answer"><p>A plane wave arriving at angle <span class="math notranslate nohighlight">\(\theta\)</span> reaches the far element after traveling an extra path <span class="math notranslate nohighlight">\(d\sin\theta\)</span>, where <span class="math notranslate nohighlight">\(d\)</span> is the baseline. That extra path is a measurable phase shift between the two channels.</p></div>
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<summary><strong>8. State the interferometer relation and its inversion for bearing.</strong></summary>
<div class="card-answer"><p><span class="math notranslate nohighlight">\(\Delta\phi = \frac{2\pi d}{\lambda}\sin\theta\)</span>, inverted to <span class="math notranslate nohighlight">\(\theta = \arcsin\!\left(\frac{\lambda\,\Delta\phi}{2\pi d}\right)\)</span>. Measure one number, <span class="math notranslate nohighlight">\(\Delta\phi\)</span>, and solve for the angle <span class="math notranslate nohighlight">\(\theta\)</span>.</p></div>
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<summary><strong>9. Why does a longer baseline give a finer bearing?</strong></summary>
<div class="card-answer"><p>Angle accuracy scales like <span class="math notranslate nohighlight">\(\lambda/(2\pi d)\)</span>: a fixed phase-measurement error maps to a smaller angle error as <span class="math notranslate nohighlight">\(d/\lambda\)</span> grows. Long baselines reach sub-degree accuracy, far past amplitude comparison.</p></div>
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<summary><strong>10. What is the phase-wrap (ambiguity) problem?</strong></summary>
<div class="card-answer"><p>A phase meter cannot tell <span class="math notranslate nohighlight">\(\Delta\phi\)</span> from <span class="math notranslate nohighlight">\(\Delta\phi + 2\pi\)</span> — phase is known only mod <span class="math notranslate nohighlight">\(2\pi\)</span>, folding into <span class="math notranslate nohighlight">\([-\pi,\pi]\)</span>. So several arrival angles share one reading, and the inversion can pick the wrong one.</p></div>
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<summary><strong>11. What baseline keeps the bearing unambiguous over <span class="math notranslate nohighlight">\(\pm 90^\circ\)</span>, and why?</strong></summary>
<div class="card-answer"><p><span class="math notranslate nohighlight">\(d \le \lambda/2\)</span>. Unambiguity requires <span class="math notranslate nohighlight">\(|\Delta\phi| \le \pi\)</span>; setting <span class="math notranslate nohighlight">\(\sin\theta = 1\)</span> in the relation gives <span class="math notranslate nohighlight">\(d \le \lambda/2\)</span>. But that is a short baseline, so it is coarse — accuracy and unambiguity pull opposite ways.</p></div>
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<summary><strong>12. How does a multi-baseline array resolve the ambiguity?</strong></summary>
<div class="card-answer"><p>The <strong>short</strong> pair (<span class="math notranslate nohighlight">\(d \le \lambda/2\)</span>) gives a coarse, unambiguous bearing that predicts which <span class="math notranslate nohighlight">\(2\pi\)</span> cycle the <strong>long</strong> pair is in; unwrap the long pair with that cycle and invert for a fine bearing. Short pair picks the cycle; long pair sets the precision.</p></div>
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<summary><strong>13. Compare amplitude comparison and interferometry on accuracy and failure mode.</strong></summary>
<div class="card-answer"><p>Amplitude comparison reads a power ratio — coarse (<span class="math notranslate nohighlight">\(\sim 10\text{–}30^\circ\)</span>), fails on pattern-calibration error. Interferometry reads phase across a baseline — fine (<span class="math notranslate nohighlight">\(<1^\circ\)</span>), fails on phase wrap. Both are passive and single-pulse; systems often amplitude-compare for the quadrant, then interferometer-refine.</p></div>
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