# Lesson 22 Flashcards

Click a question to reveal the answer.

<div data-flashcards data-deck="b3l22"></div>

<details>
<summary><strong>1. What are the five components of an aircraft IR signature?</strong></summary>
<div class="card-answer"><p>Hot parts (nozzle/turbine), exhaust plume, airframe skin emission, reflected sunlight, and reflected sky/earthshine — three emitters and two reflectors.</p></div>
</details>

<details>
<summary><strong>2. In which band does each of the three emitters dominate?</strong></summary>
<div class="card-answer"><p>Hot parts and the plume dominate in the MWIR (3–5 µm); the airframe skin dominates in the LWIR (8–12 µm).</p></div>
</details>

<details>
<summary><strong>3. State the in-band intensity ranking rule and name each factor.</strong></summary>
<div class="card-answer"><p><span class="math notranslate nohighlight">\(I_{\text{band}} \propto \varepsilon \cdot A \cdot f_{\text{band}}(T) \cdot \sigma T^{4}\)</span>: <span class="math notranslate nohighlight">\(\varepsilon\)</span> emissivity (radiating efficiency), <span class="math notranslate nohighlight">\(A\)</span> projected area seen (where aspect enters), <span class="math notranslate nohighlight">\(f_{\text{band}}(T)\)</span> band fraction (set by Wien), and <span class="math notranslate nohighlight">\(\sigma T^{4}\)</span> total output that explodes with temperature.</p></div>
</details>

<details>
<summary><strong>4. Which factor lets a small hot nozzle outshine the large cool skin per unit area?</strong></summary>
<div class="card-answer"><p>The <span class="math notranslate nohighlight">\(\sigma T^{4}\)</span> term — radiated power scales with the fourth power of absolute temperature, so temperature dominates over area.</p></div>
</details>

<details>
<summary><strong>5. Roughly what temperature do hot parts run, and what band do they peak in?</strong></summary>
<div class="card-answer"><p>About 700–900 K, peaking in the MWIR near 3–4 µm. Small area, but the <span class="math notranslate nohighlight">\(T^{4}\)</span> term makes them brilliant.</p></div>
</details>

<details>
<summary><strong>6. At what wavelength does the exhaust plume radiate, and why?</strong></summary>
<div class="card-answer"><p>Near 4.3 µm in the MWIR — the CO₂ emission band of the exhaust gas (shifted by Doppler and pressure). The ~800 K continuum peak sits around 3.6 µm.</p></div>
</details>

<details>
<summary><strong>7. Why does the airframe skin set the all-aspect signature?</strong></summary>
<div class="card-answer"><p>It radiates at near-ambient temperature (up to ~330 K subsonic) in the LWIR over a large area and is visible from every aspect, so it carries the beam and head-on signature. You cannot point it away.</p></div>
</details>

<details>
<summary><strong>8. When and in which band does reflected sunlight matter?</strong></summary>
<div class="card-answer"><p>During the day in the MWIR, where it can rival a ~300 K graybody with <span class="math notranslate nohighlight">\(\varepsilon \approx 0.5\)</span>; in the LWIR it is negligible against the surface's own thermal emission.</p></div>
</details>

<details>
<summary><strong>9. Why is an aircraft a bright MWIR target from the stern but weaker from the beam?</strong></summary>
<div class="card-answer"><p>From astern the sensor looks up the tailpipe at the exposed hot nozzle and plume; from the beam those are masked and only the skin (LWIR) remains. Projected area <span class="math notranslate nohighlight">\(A\)</span> toward the sensor changes with aspect.</p></div>
</details>

<details>
<summary><strong>10. How does look-up versus look-down change detectability?</strong></summary>
<div class="card-answer"><p>Look-up places the target on cold sky for high contrast and easy detection; look-down places it on warm cluttered terrain for low contrast and hard detection (the penetrator's friend).</p></div>
</details>

<details>
<summary><strong>11. What is thermal crossover?</strong></summary>
<div class="card-answer"><p>The moments — about an hour after sunrise and after sunset — when skin and background temperatures become equal, so the LWIR contrast <span class="math notranslate nohighlight">\(\Delta T\)</span> goes to zero and the airframe blends into its background.</p></div>
</details>

<details>
<summary><strong>12. Why is midday negative contrast and night positive contrast in the LWIR?</strong></summary>
<div class="card-answer"><p>Midday the sun-baked terrain is hotter than the skin, so the target reads cold (negative <span class="math notranslate nohighlight">\(\Delta T\)</span>); at night the terrain radiates to the cold sky and drops below the skin, so the target reads warm (positive <span class="math notranslate nohighlight">\(\Delta T\)</span>).</p></div>
</details>

<details>
<summary><strong>13. If you time an ingress at thermal crossover, are you invisible in every band?</strong></summary>
<div class="card-answer"><p>No — crossover only zeroes the LWIR skin contrast. The plume and hot parts still shout in the MWIR. You cannot disappear in every band at once.</p></div>
</details>

<details>
<summary><strong>14. In the demo diurnal model, what are the two crossover times and what do they correspond to?</strong></summary>
<div class="card-answer"><p>About 7.5 h and 19.5 h — roughly one hour after sunrise and one hour after sunset.</p></div>
</details>

<details>
<summary><strong>15. Name one suppression counter for each managed component.</strong></summary>
<div class="card-answer"><p>Hot parts: shield the nozzle / avoid afterburner. Plume: mix with bypass air to cool it / route over the airframe. Skin: low-emissivity coatings. Reflections: manage geometry and finish to kill sunglint. For an LO bomber like the B-21 these are baked into the airframe (Lesson 24 / IRCM).</p></div>
</details>
