# Lesson 25 Flashcards

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<summary><strong>1. What is radar cross section (RCS)?</strong></summary>
<div class="card-answer"><p>The target's <em>effective echo area</em> — the size of a fictitious perfect reflector that would return the same echo power. It is not physical size, and it varies with aspect, frequency, and polarization.</p></div>
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<summary><strong>2. What are the units of RCS, and what is 0 dBsm?</strong></summary>
<div class="card-answer"><p>dBsm — decibels relative to one square meter. <span class="math notranslate nohighlight">\(0\ \text{dBsm} = 1\ \text{m}^2\)</span>. The log scale is used because RCS spans many orders of magnitude.</p></div>
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<summary><strong>3. Place these on the dBsm ladder: insect, bird, human, fighter, ship, LO aircraft.</strong></summary>
<div class="card-answer"><p>Insect <span class="math notranslate nohighlight">\(\approx -40\)</span> dBsm, bird <span class="math notranslate nohighlight">\(\approx -20\)</span>, human <span class="math notranslate nohighlight">\(\approx 0\)</span>, fighter <span class="math notranslate nohighlight">\(\approx +7\)</span> (~5 m²), ship <span class="math notranslate nohighlight">\(\approx +30\)</span> to <span class="math notranslate nohighlight">\(+40\)</span>, LO "marble-class" aircraft <span class="math notranslate nohighlight">\(\approx -30\)</span> dBsm.</p></div>
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<summary><strong>4. State the three-factor rule for RCS and name each factor.</strong></summary>
<div class="card-answer"><p><span class="math notranslate nohighlight">\(\sigma = A_\text{geo} \times \Gamma \times D\)</span>: geometric (projected/intercepted) cross section, reflectivity (fraction re-radiated), and directivity (fraction of the echo aimed back at the radar).</p></div>
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<summary><strong>5. Which of the three RCS factors buys orders of magnitude, and what design technique attacks it?</strong></summary>
<div class="card-answer"><p>Directivity <span class="math notranslate nohighlight">\(D\)</span> — and <strong>shaping</strong> attacks it. Geometric area and reflectivity only buy factors; directivity buys orders of magnitude, so shaping is the foundation of LO design and absorber is the finishing coat.</p></div>
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<summary><strong>6. Give the peak-RCS formula and behavior for a flat plate.</strong></summary>
<div class="card-answer"><p>Broadside, <span class="math notranslate nohighlight">\(\sigma = 4\pi A^2/\lambda^2\)</span> — a huge specular spike that collapses within degrees off-normal (loud but narrow). A 1 m² plate at X-band (<span class="math notranslate nohighlight">\(\lambda = 3\)</span> cm) gives <span class="math notranslate nohighlight">\(\approx 14{,}000\)</span> m² (~+41.5 dBsm).</p></div>
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<summary><strong>7. Why is a sphere the calibration reference target?</strong></summary>
<div class="card-answer"><p>Its RCS is <span class="math notranslate nohighlight">\(\sigma = \pi r^2\)</span> and is aspect-independent — no directivity spike — so it returns a known, constant echo from every angle.</p></div>
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<summary><strong>8. Why is a corner (dihedral/trihedral) more dangerous to LO than a flat plate?</strong></summary>
<div class="card-answer"><p>Its double-bounce geometry retroreflects energy straight back at the radar over a <em>wide</em> range of angles, whereas a plate is loud only in a narrow specular spike.</p></div>
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<summary><strong>9. Where do aircraft accidentally grow corners?</strong></summary>
<div class="card-answer"><p>Tail-fuselage junctions, open weapons bays, pylons, and inlets (a cavity acts as a corner). First commandment of shaping: do not present a right angle.</p></div>
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<summary><strong>10. Name the three scattering regimes and what governs RCS in each.</strong></summary>
<div class="card-answer"><p>Optical (<span class="math notranslate nohighlight">\(L \gg \lambda\)</span>, shape rules), resonance (<span class="math notranslate nohighlight">\(L \sim \lambda\)</span>, the whole body rings and shaping loses grip), Rayleigh (<span class="math notranslate nohighlight">\(L \ll \lambda\)</span>, only gross size matters, <span class="math notranslate nohighlight">\(\sigma \sim f^4\)</span>).</p></div>
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<summary><strong>11. Why are VHF early-warning radars a counter-stealth capability?</strong></summary>
<div class="card-answer"><p>At VHF the wavelength is comparable to airframe features, dragging a fighter-sized shaped target toward the resonance regime, where optical-regime shaping tricks lose much of their leverage.</p></div>
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<summary><strong>12. What does an RCS aspect pattern look like, and where do max and median live?</strong></summary>
<div class="card-answer"><p>Narrow specular spikes (tens of dB tall, at facet normals) over a deep, noisy floor of edges and traveling waves. The <strong>max</strong> lives in the spikes; the <strong>median</strong> describes the floor a search radar sees most of the time.</p></div>
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<summary><strong>13. Why must the mean RCS be computed in the linear domain, and why prefer the median?</strong></summary>
<div class="card-answer"><p>Averaging must be done in linear m² — <span class="math notranslate nohighlight">\(10\log_{10}(\overline{10^{\sigma/10}})\)</span>. A few narrow spikes drag the linear mean many dB above the median; the median tracks the floor a search radar actually sees, so it is the honest planning number.</p></div>
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<summary><strong>14. State the fourth-power detection-range law and what a 10 / 30 dB RCS cut buys.</strong></summary>
<div class="card-answer"><p><span class="math notranslate nohighlight">\(R_\text{max} \propto \sigma^{1/4}\)</span>. Cutting median RCS 10 dB drops range to ~56%; 30 dB to ~18%. Detection <em>area</em> falls as <span class="math notranslate nohighlight">\(\sigma^{1/2}\)</span>, collapsing IADS rings. Stealth does not make you invisible — it shrinks the rings.</p></div>
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