ECE 495 — Electromagnetic Warfare and Survivability
Block 1: Radar Fundamentals Lesson 5: Doppler, MTI, and Pulse-Doppler
Juan Jurado, Col, USAF, Ph.D.
Permanent Professor and Head
Electrical and Computer Engineering Fall 2026
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Block 1 · Lesson 5 · Where We Left Off
Where We Left Off
L4 gave us the pulse train — a sampler in time.
Each pulse carries a phase. Across pulses, that phase moves whenever the target does.
Today
The Doppler shift, MTI filtering, and pulse-Doppler
processing — the tools that separate the “movers”
from clutter.
Block 1 · Lesson 5 · Objectives
Lesson Objectives
By the end of this lesson, you will be able to:
Compute the Doppler shift from a radial velocity
Explain how a single delay-line MTI rejects ground clutter
Identify blind speeds and how PRF moves them around
Describe pulse-Doppler processing as an FFT across pulses
Clutter is stationary. You are not.
Block 1 · Lesson 5 · Part One
The Second Observable
Range tells the radar where something is. The phase that walks across the pulse train tells it what that something is doing — and that is what pulls a target out of the whole Earth behind it.
Block 1 · Lesson 5 · Doppler Shift
The Doppler Effect on Radar Returns
A target moving radially at $v_r$ shifts the carrier by:
Doppler shift
\[ f_d = \frac{2 \, v_r}{\lambda} \]
The factor of 2 is the two-way path. X-band ($\lambda = 3$ cm) examples:
$v_r = 300$ m/s $\;\Rightarrow\; f_d = 20$ kHz
$v_r = 30$ m/s $\;\Rightarrow\; f_d = 2.0$ kHz
Range tells you where; Doppler tells you what.
Block 1 · Lesson 5 · Clutter
Clutter vs Targets
A radar looking down sees everything, not just the threat.
Ground clutter — huge RCS, $f_d \approx 0$
Weather, sea, foliage — distributed, small $f_d$
Aircraft — modest RCS, $f_d$ from hundreds of Hz to tens of kHz
The aircraft return is buried in clutter on the basis of amplitude alone. Doppler separates the two.
Clutter is a confidently stationary signal the radar must learn to ignore.
Block 1 · Lesson 5 · Part Two
MTI and Its Price
One subtraction removes the clutter. The same subtraction removes anything unlucky enough to share its Doppler — and the PRF decides who that is.
Block 1 · Lesson 5 · MTI Canceller
Single Delay-Line MTI Canceller
Subtract one pulse return from the next — whatever did not change cancels.
The canceller
\[ y[n] = x[n] - x[n-1] \]
Response, $T = $ PRI
\[ |H(f)| = 2 \, |\sin(\pi f T)| \]
Notches at $f = 0, \, \text{PRF}, \, 2\,\text{PRF}, \ldots$ — stationary clutter is killed
Passes Doppler shifts away from those notches — movers survive
Cheap to implement: one PRI of memory and a subtractor
Higher-order cancellers and adaptive MTI go deeper.
Block 1 · Lesson 5 · The Notch
What the Antenna Hears
One range bin at X-band, PRF $= 1$ kHz, sorted by Doppler. Three returns, one axis.
return power
ground clutter0 m/s
convoy22 m/s
helo30 m/s
0
15
30
45
60
radial velocity (m/s)
The clutter dwarfs both movers on amplitude. What can you subtract that takes the ridge and leaves the rest?
Block 1 · Lesson 5 · The Notch
The Notch Giveth and Taketh
Drop $|H(f)| = 2|\sin(\pi f T)|$ on top: it is zero at $0, \text{PRF}, 2\,\text{PRF},\ldots$ — every 15 m/s at this PRF.
return power
|H(f)|
cancelled0 m/s
convoy22 m/s · survives
helo30 m/s · blind speed
0
15
30
45
60
radial velocity (m/s)
The helo was never detected and never reported. It was filtered.
Block 1 · Lesson 5 · Blind Speeds
Blind Speeds
A target whose Doppler shift lands on any MTI notch looks stationary.