# Lesson 6 Flashcards — AC Circuit Analysis

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<summary><strong>1. Write the general equation of an AC signal and name each term.</strong></summary>
<div class="card-answer"><p><span class="math notranslate nohighlight">\(v(t) = V_\text{bias} + A\cos(2\pi f t + \phi)\)</span> — DC offset, amplitude, frequency, and phase shift. The period is <span class="math notranslate nohighlight">\(T = 1/f\)</span>.</p></div>
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<summary><strong>2. How do you compute a phase shift from a time offset?</strong></summary>
<div class="card-answer"><p><span class="math notranslate nohighlight">\(\phi = (2\pi/T)\,\Delta t\)</span>, or in degrees <span class="math notranslate nohighlight">\(\phi^\circ = (360^\circ/T)\,\Delta t\)</span>. Measure <span class="math notranslate nohighlight">\(\Delta t\)</span> from the origin <strong>leftward</strong> to the nearest positive peak — that direction <em>is</em> the convention, and measuring rightward instead flips the sign. So a peak left of the origin gives <span class="math notranslate nohighlight">\(\phi > 0\)</span> and the wave <strong>leads</strong>; a peak to the right gives <span class="math notranslate nohighlight">\(\phi < 0\)</span> and it <strong>lags</strong>.</p></div>
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<summary><strong>3. How do you convert between sine and cosine form?</strong></summary>
<div class="card-answer"><p><span class="math notranslate nohighlight">\(\sin(x) = \cos(x - 90^\circ)\)</span>. Problems appear in both forms — convert to cosine first and stay there.</p></div>
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<summary><strong>4. Why is nearly all generated and transmitted power AC?</strong></summary>
<div class="card-answer"><p>Generators produce it naturally by spinning a coil in a magnetic field, and transformers — which do nothing with DC — are what make long-distance transmission affordable. So the wall outlet is AC too, and every device you own converts it back to DC itself (Lesson 10). <strong>DC is what devices want; AC is how power gets to them.</strong></p></div>
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<summary><strong>5. For a resistor, what is the phase relationship between voltage and current?</strong></summary>
<div class="card-answer"><p>They are <strong>in phase</strong> — peaking together and crossing zero together. Every Block 1 analysis tool therefore applies to AC resistive circuits unchanged.</p></div>
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<summary><strong>6. What is the RMS value of a signal, physically?</strong></summary>
<div class="card-answer"><p>The DC voltage that would deliver the <strong>same average power</strong> to the same resistor.</p></div>
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<summary><strong>7. Give the RMS value of a sinusoid.</strong></summary>
<div class="card-answer"><p><span class="math notranslate nohighlight">\(V_\text{rms} = V_\text{pk}/\sqrt{2}\)</span>. This factor holds <strong>only</strong> for sinusoids.</p></div>
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<summary><strong>8. A signal has a DC bias on top of a sinusoid. What is its RMS value, and what power does it deliver to a resistor?</strong></summary>
<div class="card-answer"><p>Use the general form <span class="math notranslate nohighlight">\(V_\text{rms} = \sqrt{V_\text{bias}^2 + V_\text{pk}^2/2}\)</span> — the <span class="math notranslate nohighlight">\(V_\text{pk}/\sqrt{2}\)</span> you already know is just its bias-free case. Equivalently, the DC and AC powers <strong>add</strong> in a resistor: <span class="math notranslate nohighlight">\(P = V_\text{bias}^2/R + \left(V_\text{pk}/\sqrt{2}\right)^2/R\)</span>, which is the same number as <span class="math notranslate nohighlight">\(V_\text{rms}^2/R\)</span>. The bias is <em>not</em> part of the <span class="math notranslate nohighlight">\(\sqrt{2}\)</span> relationship — handle it separately.</p></div>
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<summary><strong>9. A US wall outlet is '120 volts'. What is the peak voltage?</strong></summary>
<div class="card-answer"><p><span class="math notranslate nohighlight">\(V_\text{pk} = 120\sqrt{2} \approx 170\ \text{V}\)</span>. Every AC rating is RMS unless stated otherwise.</p></div>
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<summary><strong>10. At what frequency does instantaneous power in a resistor oscillate?</strong></summary>
<div class="card-answer"><p>At <strong>twice</strong> the signal frequency, and it is never negative. It swings between 0 and <span class="math notranslate nohighlight">\(V_\text{pk}^2/R\)</span>, averaging <span class="math notranslate nohighlight">\(V_\text{pk}^2/2R\)</span>.</p></div>
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<summary><strong>11. Once you are working in RMS, what does the power equation look like?</strong></summary>
<div class="card-answer"><p>Exactly like the DC one: <span class="math notranslate nohighlight">\(P = V_\text{rms}I_\text{rms} = I_\text{rms}^2R = V_\text{rms}^2/R\)</span>.</p></div>
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