# Project 1 — Power Distribution

<p class="block-synopsis">Design the power system for a classified prototype aerial platform, then switch sides of the table and evaluate the competing proposals as a government customer.</p>

:::{admonition} At a glance
:class: key-concept

**Groups of 2–4.** Three Gradescope submissions, **1 point each**.
Kicked off at **Lesson 12**; work days are **Lessons 13 and 14**.
Submission 1 is due **Monday 14 September at 2359**; Submissions 2–3 are due
**Wednesday 16 September at 2359**. Gradescope is authoritative for all deadlines.
:::

## The Problem

Your team works both sides of the contracting process.

- **Part 1 — you are the contractor.** Design a power system that energizes eight electrical
  loads to specification. You want a better design than the other teams.
- **Part 2 — you are the government evaluator.** You receive the other teams' proposals and
  rate them objectively with a decision matrix.

You do not see anyone else's design until your Part 1 is submitted.

## System Requirements

The system must properly energize the following eight loads. All AC voltages are RMS and apply
to a 60 Hz system. Label the loads A–H in your design, matching the proposal diagrams.

| Load | Description | Voltage | Specification |
| --- | --- | --- | --- |
| A | Recirculation fans | 240 V<sub>rms</sub> | 8 kW, pf = 0.8 lagging |
| B | Fuel pumps | 240 V<sub>rms</sub> | 12 kVA, pf = 0.6 lagging |
| C | Cabin lighting | 120 V<sub>rms</sub> | 6 kW, pf = 0.8 lagging |
| D | Cabin fans | 120 V<sub>rms</sub> | 5 hp, $\eta = 88.89\%$, pf = 0.8 lagging |
| E | Auto-pilot & controls | 48 V DC | $R = 2\ \Omega$ |
| F | Brake power | 48 V DC | 0.75 hp, $\eta = 85\%$ |
| G | Communications | 24 V DC | 500 W |
| H | Flight displays | 24 V DC | 25 A |

Every load type here is one you learned to handle in Lessons 6–10. Nothing in this table is new.

## Constraints

A proposed system must comply with **all** of the following:

- All loads connected to a bus and powered to the Table 1 specifications.
- Powered by a generator **not exceeding 30 kW of real power** during normal operation,
  attached to either a 240 V<sub>rms</sub> or 120 V<sub>rms</sub> bus.
- A resistor of **0.016 Ω – 0.022 Ω** between the generator and the first bus, to capture wiring
  losses. No cost is associated with this resistor.
- Only the **COTS converters** listed in Table 2 of the handout may be used — in any quantity; the same catalog item may be used more than once, and each instance is priced and counted separately.
- Every load, bus, and piece of conversion equipment gets **its own circuit breaker**.
- Cost of conversion and protection must not exceed **\$500,000**.
- Volume of conversion equipment must not exceed **25 m³**.

:::{admonition} Compliance is not a score
:class: key-concept

A design that violates any constraint is not a *worse* design — it is a **non-compliant** one.
Check compliance before you spend any time optimizing.
:::

## Evaluation Criteria

The solicitation states the priority directly: **cost is weighted 2× efficiency, and efficiency
is weighted 2× volume.** That is a ratio of 4 : 2 : 1, so:

| Measure | Ratio | Weight | Direction | Normalize with |
| --- | --- | --- | --- | --- |
| Cost | 4 | 0.571 | smaller is better | $x_{\min}/x$ |
| Efficiency | 2 | 0.286 | bigger is better | $x/x_{\max}$ |
| Volume | 1 | 0.143 | smaller is better | $x_{\min}/x$ |

Two of the three are smaller-is-better. Getting a direction backward is the fastest way to lose
the Submission 2 point — see [Objective 1.8](../Block1Reading/Obj08/ECE215_Obj08_Reading).

## Method

Work **backward from the loads**, exactly as in Lessons 8–10:

1. Find the real power and current each load demands.
2. Group loads onto buses by voltage.
3. Work back through each converter: $P_{in} = P_{out}/\eta$.
4. Sum at each bus, then step back to the generator.
5. Add the wiring-resistor loss **last**, using the *generator* current: $P = I^2R$.
6. Verify the generator total is under 30 kW.

:::{admonition} The two mistakes teams make every semester
:class: key-concept

**Summing apparent power against the generator limit.** The 30 kW cap is on **real power**.
Load B is given as 12 kVA at pf = 0.6 — that is 7.2 kW real, not 12. Sum $P$ against the limit,
but size the *wiring* from the actual current, which follows $S$.

**Using load current in the wiring-resistor loss.** That resistor sits between the generator and
the first bus, so it carries the **total generator current** — not any individual load's.
:::

## Deliverables

Three Gradescope submissions, **1 point each**, graded on specifications.

### Submission 1 — system design *(group)*

Due **Monday 14 September at 2359** (before Lesson 14). Upload **two files**: your design
and analysis as a **PDF**, and the completed **Design Summary workbook** built from the
template below.

- [ ] System design is easy to read, clearly labeled, and meets every design requirement.
      See the example bus diagram (Figure 1) in the handout below for the drawing conventions.
- [ ] Mathematical analysis provided, legible, and clearly labeled.

Gradescope returns an automatic **consistency report** on your workbook — whether your own
numbers agree with each other and with the handout's catalogs. It is **advisory feedback
only**; your instructors grade the two specifications above.

### Submission 2 — decision matrix *(group)*

- [ ] Decision matrix filled out correctly. **Auto-graded — trivial math errors will not earn
      credit.** Rounding errors are fine.
- [ ] Supporting analysis provided, as clearly labeled handwriting or an organized spreadsheet.

### Submission 3 — engineering analysis *(individual)*

- [ ] Questions answered correctly with **concise** technical writing. Lengthy responses will
      not earn credit.

## Authorized Resources

- Calculator and computational tools — Excel, MATLAB, Google Sheets, Python
- The ECE 215 equation sheet
- Slides, class notes, and the readings on this site
- Practice problems
- **GenAI: Level 2 only** (see the AW GenAI policy)
- Collaboration with cadets **in your project group**, and EI from ECE instructors

:::{admonition} Note on seeking EI from ECE 315 instructors
:class: warning

This project has differences in power computations from the ECE 315 Project 1. Mention that you
are in ECE 215 when you ask.
:::

## Files

<embed src="../_static/ECE215_Project1_pt1.pdf" width="100%" height="600px" type="application/pdf">

- Handout, Document 1 of 2 — [ECE215_Project1_pt1.pdf](../_static/ECE215_Project1_pt1.pdf)
- Part 1 spreadsheet — [Submission 1 Design Summary template](../_static/ECE215_Project1_Submission1_Template.xlsx)
- Part 2 spreadsheet — [Submission 2 Excel template](../_static/ECE215_Project1_Submission2_Template.xlsx)
- Handout, Document 2 of 2 — [ECE215_Project1_pt2.pdf](../_static/ECE215_Project1_pt2.pdf)
  — **password-protected**

**Document 2 of 2 — the competing contractor proposals — is the file above, and it opens with
the password shown in your Submission 1 results on Gradescope.** Turn in Submission 1 (the
design PDF and the completed Design Summary workbook), then read the password off your
submission results and open the packet. No team sees another design before its own is
submitted.
