# Lesson 17 Flashcards — Analog Filters

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<summary><strong>1. How does a real filter differ from an ideal one?</strong></summary>
<div class="card-answer"><p>A real filter <strong>rolls off</strong> gradually — there is no wall. Frequencies near the cutoff are partially attenuated, and sharpening the transition costs more components, size, and money.</p></div>
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<summary><strong>2. Define the cutoff frequency.</strong></summary>
<div class="card-answer"><p>The frequency at which output <strong>power</strong> falls to half the passband value. Since power goes as voltage squared, the voltage falls to <span class="math notranslate nohighlight">\(1/\sqrt{2} = 0.707\)</span>.</p></div>
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<summary><strong>3. Why is cutoff also called the −3 dB point?</strong></summary>
<div class="card-answer"><p>Because <span class="math notranslate nohighlight">\(10\log_{10}(0.5) = -3\ \text{dB}\)</span>. 'Cutoff', 'corner frequency', 'half-power point', and '−3 dB point' all name the same thing.</p></div>
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<summary><strong>4. What kind of filter is an R-C circuit with the output across the capacitor?</strong></summary>
<div class="card-answer"><p><strong>Low-pass.</strong> At DC the capacitor is an open, so the output sees the full source; at high frequency it is a short and the output goes to zero.</p></div>
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<summary><strong>5. What kind of filter is a C-R circuit with the output across the resistor?</strong></summary>
<div class="card-answer"><p><strong>High-pass.</strong> Same two components as the R-C case — the filter type depends on <em>where you take the output</em>.</p></div>
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<summary><strong>6. Give the cutoff frequency for R-C and C-R circuits.</strong></summary>
<div class="card-answer"><p><span class="math notranslate nohighlight">\(f_\text{cutoff} = 1/(2\pi RC)\)</span>. At that frequency <span class="math notranslate nohighlight">\(|Z_C| = R\)</span> and the two elements contribute equally.</p></div>
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<summary><strong>7. Give the cutoff frequency for R-L and L-R circuits.</strong></summary>
<div class="card-answer"><p><span class="math notranslate nohighlight">\(f_\text{cutoff} = R/(2\pi L)\)</span>.</p></div>
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<summary><strong>8. Give the quick test for identifying a filter type by inspection.</strong></summary>
<div class="card-answer"><p>Ask what the reactive element does at <strong>DC</strong> (capacitor → open, inductor → short), then ask whether the output survives. Survives at DC means low-pass; killed at DC means high-pass.</p></div>
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<summary><strong>9. What is the gain one decade past the cutoff of a first-order filter?</strong></summary>
<div class="card-answer"><p><span class="math notranslate nohighlight">\(1/\sqrt{1+10^2} = 0.0995\)</span>, i.e. <strong>−20 dB</strong>. One decade costs 20 dB — the standard first-order rolloff.</p></div>
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<summary><strong>10. Your measured cutoff differs from the computed one. Is that a problem?</strong></summary>
<div class="card-answer"><p>Not necessarily. Component tolerances (a ±10% capacitor moves the cutoff ±10%) plus probe and breadboard stray capacitance explain modest discrepancies. A disagreement you can <em>explain</em> is a good result. (You will see this first-hand at the Lesson 19 lab.)</p></div>
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