# Lesson 34 Flashcards — The Radar Range Equation

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<summary><strong>1. How does a radar link differ from a communications link?</strong></summary>
<div class="card-answer"><p>The signal makes the trip <strong>twice</strong> — out to the target and back — so spreading loss applies twice, giving <span class="math notranslate nohighlight">\(1/R^4\)</span> instead of <span class="math notranslate nohighlight">\(1/R^2\)</span>.</p></div>
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<summary><strong>2. What is radar cross section?</strong></summary>
<div class="card-answer"><p>A measure of how much power a target scatters back, in <strong>square meters</strong> — but it is <em>not</em> physical size. It varies enormously with aspect (the direction the radar views the target from), shape, and coatings. The slides write it <span class="math notranslate nohighlight">\(\sigma\)</span>; the equation sheet writes <em>RCS</em>.</p></div>
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<summary><strong>3. Write the radar range equation.</strong></summary>
<div class="card-answer"><p><span class="math notranslate nohighlight">\(P_R = P_T G^2 \sigma \lambda^2/[(4\pi)^3 R^4]\)</span>.</p></div>
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<summary><strong>4. Why does G appear squared in the radar range equation?</strong></summary>
<div class="card-answer"><p>Because the <strong>same antenna</strong> both transmits and receives. The equation sheet prints it as <span class="math notranslate nohighlight">\(G_T^2\)</span>.</p></div>
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<summary><strong>5. Give the maximum detection range.</strong></summary>
<div class="card-answer"><p><span class="math notranslate nohighlight">\(R_{\max} = \sqrt[4]{P_T G^2 \sigma \lambda^2/[(4\pi)^3 P_{R,\min}]}\)</span> — <strong>every term sits under a fourth root</strong>. <span class="math notranslate nohighlight">\(P_{R,\min}\)</span> is the radar's sensitivity, its minimum detectable signal.</p></div>
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<summary><strong>6. What must you do to double a radar's detection range by transmit power alone?</strong></summary>
<div class="card-answer"><p>Raise <span class="math notranslate nohighlight">\(P_T\)</span> by a factor of <strong>16</strong>. That is the fourth root working against the designer.</p></div>
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<summary><strong>7. Cutting RCS by a factor of 16 does what to detection range?</strong></summary>
<div class="card-answer"><p><strong>Halves</strong> it. The target's lever is equally fourth-rooted — but it is one-time engineering rather than a continuing power bill, which is why stealth wins.</p></div>
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<summary><strong>8. A 100× RCS reduction cuts range by how much?</strong></summary>
<div class="card-answer"><p><span class="math notranslate nohighlight">\((1/100)^{1/4} = 0.316\)</span>, so range drops to about <strong>a third</strong>. Modest on paper, but the defended <em>area</em> scales as <span class="math notranslate nohighlight">\(R^2\)</span> and so shrinks tenfold.</p></div>
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<summary><strong>9. On an RCS polar plot, what do the angle and the radius show?</strong></summary>
<div class="card-answer"><p>The angle is the <strong>aspect</strong> — where the radar is, as seen from the aircraft, with 0° at the nose and 180° at the tail. The radius is <span class="math notranslate nohighlight">\(\sigma\)</span> in square meters.</p></div>
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<summary><strong>10. What is the fuzzball on an RCS plot, and when do you use it?</strong></summary>
<div class="card-answer"><p>The low RCS level the target shows at every aspect between the narrow <strong>spikes</strong>. Use the fuzzball value unless the problem names an aspect that falls on a spike.</p></div>
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<summary><strong>11. What is the depression angle named on an RCS plot?</strong></summary>
<div class="card-answer"><p>How far below the aircraft's horizon the radar sits, looking up at it. A plot is drawn for one frequency band and one depression angle, so pick the plot that matches the problem.</p></div>
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<summary><strong>12. How does an RWR detecting a radar differ from a radar detecting an aircraft?</strong></summary>
<div class="card-answer"><p>The RWR is a <strong>one-way</strong> problem (<span class="math notranslate nohighlight">\(1/R^2\)</span>); the radar is <strong>two-way</strong> (<span class="math notranslate nohighlight">\(1/R^4\)</span>). Which one detects first depends on the two sensitivities and on <span class="math notranslate nohighlight">\(\sigma\)</span> — compute both ranges.</p></div>
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<summary><strong>13. How do you find the range at which an RWR detects a radar?</strong></summary>
<div class="card-answer"><p>Friis solved for <span class="math notranslate nohighlight">\(R\)</span>, with the radar as the transmitter: <span class="math notranslate nohighlight">\(R = \frac{\lambda}{4\pi}\sqrt{P_T G\,G_R/P_{R,\min}}\)</span>, using the RWR's own antenna gain <span class="math notranslate nohighlight">\(G_R\)</span> and sensitivity.</p></div>
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<summary><strong>14. Why is listening free for the aircraft?</strong></summary>
<div class="card-answer"><p>Because the radar <strong>has to transmit</strong> to do its job. Transmitting is what gives you away — the foundation of electronic support.</p></div>
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