# Lesson 36 Flashcards — Signal-to-Noise Ratio

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<summary><strong>1. Where does noise come from?</strong></summary>
<div class="card-answer"><p><strong>Thermal noise</strong> from random charge motion in any conductor above absolute zero, <strong>receiver noise</strong> from the amplifiers and other electronics in your own receiver, and <strong>sky and ground noise</strong> collected by the antenna. It is there even when nobody else is transmitting.</p></div>
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<summary><strong>2. Define SNR.</strong></summary>
<div class="card-answer"><p><span class="math notranslate nohighlight">\(SNR = P_\text{signal}/P_\text{noise}\)</span> — how loud you are talking divided by how loud everyone else is. It is dimensionless, often quoted in dB.</p></div>
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<summary><strong>3. Give the thermal noise power equation.</strong></summary>
<div class="card-answer"><p><span class="math notranslate nohighlight">\(P_\text{noise} = k\,T_\text{sys}\,BW\)</span>, with <span class="math notranslate nohighlight">\(k = 1.38\times10^{-23}\)</span> J/K, <span class="math notranslate nohighlight">\(T_\text{sys}\)</span> in kelvins, and <span class="math notranslate nohighlight">\(BW\)</span> the receiver's bandwidth in Hz. The result is in watts.</p></div>
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<summary><strong>4. What are the two levers on the noise floor?</strong></summary>
<div class="card-answer"><p><strong>Bandwidth</strong> — narrower means less noise, which is why receivers filter down to just the signal — and <strong>system temperature</strong>, which is why radio astronomy cools its receivers.</p></div>
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<summary><strong>5. Where does 'minimum detectable signal' actually come from?</strong></summary>
<div class="card-answer"><p><span class="math notranslate nohighlight">\(P_{R,\min} = SNR_{\min} \times k\,T_\text{sys}\,BW\)</span>, where <span class="math notranslate nohighlight">\(SNR_{\min}\)</span> is the minimum SNR the receiver needs. It is a property of <strong>your receiver and its bandwidth</strong>, not of the transmitter.</p></div>
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<summary><strong>6. When does a link close, or a radar detect?</strong></summary>
<div class="card-answer"><p>When <span class="math notranslate nohighlight">\(SNR \ge SNR_{\min}\)</span>. Comparing <span class="math notranslate nohighlight">\(P_R\)</span> with the sensitivity <span class="math notranslate nohighlight">\(P_{R,\min}\)</span> is the same test. A jammer adds its power to the noise and the same <span class="math notranslate nohighlight">\(SNR_{\min}\)</span> still decides: <span class="math notranslate nohighlight">\(P_R/(P_\text{noise} + P_{R,\text{jam}}) \ge SNR_{\min}\)</span>.</p></div>
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<summary><strong>7. Is SNR greater than 1 the test for detection?</strong></summary>
<div class="card-answer"><p><strong>No.</strong> <span class="math notranslate nohighlight">\(SNR_{\min}\)</span> belongs to the receiver's processing. A receiver that integrates many pulses, or de-spreads a spread-spectrum signal, can work with <span class="math notranslate nohighlight">\(SNR_{\min}\)</span> far below 1; one without that processing gain needs it above 1.</p></div>
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<summary><strong>8. Write SNR for a communications link.</strong></summary>
<div class="card-answer"><p><span class="math notranslate nohighlight">\(SNR = P_R/(k T_\text{sys} BW)\)</span> with <span class="math notranslate nohighlight">\(P_R\)</span> from Friis. Everything that helps <span class="math notranslate nohighlight">\(P_R\)</span> helps SNR, plus the new lever of reducing <span class="math notranslate nohighlight">\(BW\)</span>.</p></div>
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<summary><strong>9. Write SNR for a radar link.</strong></summary>
<div class="card-answer"><p>The same, but with <span class="math notranslate nohighlight">\(P_R\)</span> from the radar range equation — so the <span class="math notranslate nohighlight">\(R^4\)</span> carries straight through and radar SNR collapses very fast with range.</p></div>
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<summary><strong>10. Why does low observability attack detection rather than the radar itself?</strong></summary>
<div class="card-answer"><p>Because reducing the RCS, <span class="math notranslate nohighlight">\(\sigma\)</span>, attacks the <strong>numerator</strong> of the SNR expression directly, lowering received signal against a noise floor the radar cannot reduce further.</p></div>
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<summary><strong>11. Halving bandwidth improves comms range by how much? Radar range?</strong></summary>
<div class="card-answer"><p>Comms <span class="math notranslate nohighlight">\(P_R \propto 1/R^2\)</span> so range improves by <span class="math notranslate nohighlight">\(\sqrt{2}\)</span>. Radar <span class="math notranslate nohighlight">\(P_R \propto 1/R^4\)</span> so range improves only by <span class="math notranslate nohighlight">\(2^{1/4} = 1.19\)</span>.</p></div>
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<summary><strong>12. What is the golden rule when judging detection?</strong></summary>
<div class="card-answer"><p><strong>A received power means nothing alone: compare it to the noise, or to a sensitivity that already contains the noise.</strong> Detection is a signal-to-<em>noise</em> question.</p></div>
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