One $+10$ dBsm corner beside a $-20$ dBsm airframe is the signature
So LO design is a budget: every contributor under the line, loudest first
The fourth root prices it: $-20$ dB of median RCS keeps a third of the reach
This budget logic is exactly how Project 3 should argue
Fix the loudest scatterer — the rest is rounding error.
Block 3 · Lesson 26 · Where This Is Headed
Where This Is Headed: Buying the Last dBs
Shaping did the heavy lifting. What it cannot fix, materials and discipline must:
RAM: absorb what shaping could not redirect — edges, seams, inlet lips
Polarization tricks: exploit how edges and wires favor one polarization
EMCON: the loudest thing on a stealth aircraft is its own transmitter
L27 closes the RF story; L28 fuses every signature into one target
Block 3 · Lesson 26 · Quick Exercise
Quick Exercise / Type-along: Price the Budget
Type this with me — three contributors, one wallet.
% L26 type-along: itemize the budget, then price the fix.
sig_dB = [2 -7 -15]; % three contributors [dBsm]
sig = 10.^(sig_dB/10); % linear [m^2] -- sums add here
tot = sum(sig);
fprintf('Total %.3f m^2 = %.2f dBsm\n', tot, 10*log10(tot));
[~, k] = max(sig); % the tyrant of the budget
fprintf('Loudest is #%d (%+.0f dBsm) = %.1f%% of the sum\n', ...
k, sig_dB(k), 100*sig(k)/tot);
cut = 10*log10(2^4); % R ~ sigma^(1/4)
fprintf('Halving range needs %.1f dB off the TOTAL\n', cut);
new = sig;
new(k) = new(k)*10^(-cut/10); % spend it all on the loudest
fprintf('Fixing only #%d: %.2f dBsm, a %.1f dB cut\n', ...
k, 10*log10(sum(new)), 10*log10(tot/sum(new)));
You spent the whole halving cut on #1 — did the total drop that far? Why not?
What did that buy in range — and where does the next dollar go?
Block 3 · Lesson 26 · Quick Problem
Quick Problem: Nose-Sector Budget
A notional airframe’s nose-sector budget, one line per contributor family, with a serpentine duct on the table.
Engine inlet and duct: $-10$ dBsm
Radome and antennas: $-16$ dBsm
Leading edges: $-20$ dBsm
Gaps, seams, and fasteners: $-23$ dBsm
A serpentine duct and inlet screen would cut the inlet line by 10 dB
(a) The total, in m$^2$ and dBsm.
(b) The loudest line’s share of the total, in percent.
(c) Fit only the duct: the new total in dBsm, and how many dB it fell.
(a) 0.140 m$^2$ = $-8.5$ dBsm · (b) 71 % · (c) $-13.0$ dBsm, a 4.5 dB drop
Today’s Interactive Demo: Planform Alignment
Companion script:L26_PlanformAlignment.m
Live demo
Planform Alignment
usafa-ece.github.io/ece-495-ew
Block 3 · Lesson 26 · Wrap-Up
Wrap-Up
Key ideas
Five families — cavities, antennas, speculars, edges, seams — each with a verdict