Practice Problems (KEY)#

Nodes: 4 Nodes: 6
Loops: 3 Loops: 7

Nodes: 4 Nodes: 4
Loops: 1 Loops: 7


Given \(i_2 = -2\,\text{A}\), \(i_3 = -5\,\text{A}\), and \(i_4 = 4\,\text{A}\):

(a) Nodes: 3 Loops: 3
(b) KVL and KCL equations:
\(V_Q - V_P - V_R = 0\)
\(V_R - V_S = 0\)
\(V_Q - V_P - V_S = 0\)
\(I_Q + I_P = 0\)
\(-I_P - I_R - I_S = 0\)
\(-I_Q + I_R + I_S = 0\)
(c) Power consumed by each component:
\(V_S = 4\,\text{V}\), \(V_R = 4\,\text{V}\), \(V_P = 6\,\text{V}\), \(V_Q = 10\,\text{V}\)
\(I_S = 1\,\text{A}\), \(I_R = 1\,\text{A}\), \(I_P = -2\,\text{A}\), \(I_Q = 2\,\text{A}\)
\(P_S = 4\,\text{W}\), \(P_R = 4\,\text{W}\), \(P_P = 12\,\text{W}\), \(P_Q = 20\,\text{W}\)

KVL Equations |
KCL Equations |
|---|---|
\(-V_G - 2\,\text{V} + V_J = 0\) |
\(4\,\text{A} + I_H - 3\,\text{A} = 0\) |
\(2\,\text{V} - 7\,\text{V} - V_K = 0\) |
\(3\,\text{A} + I_J - 5\,\text{A} - 6\,\text{A} = 0\) |
\(-V_L + V_K + 17\,\text{V} = 0\) |
\(I_M + I_N + 5\,\text{A} = 0\) |
\(-V_J + V_L - 6\,\text{V} = 0\) |
\(6\,\text{A} - I_N - I_H = 0\) |
\(V_G = 4\,\text{V}\) |
\(I_M = -I_N - 5\,\text{A}\) |
A satellite control module is connected to a data processing element modeled as a single \(12.5\,\text{k}\Omega\) resistor (\(R_2\)). The system is powered by a \(5\,\text{V}\) solar cell (\(V_S\)). Control module options:
\(R_1 = 5\,\text{k}\Omega\)
\(R_1 = 10\,\text{k}\Omega\)
\(R_1 = 15\,\text{k}\Omega\)
(Solved in class — see lecture notes for full solution.)
Requirements:
Total current must not exceed \(250\,\mu\text{A}\)
Voltage across the control module (\(V_1\)) must be at least \(2\,\text{V}\)
(Solved in class — see lecture notes for full solution.)